↧
Answer by Per Alexandersson for Power sums and Jack symmetric functions
To turn Richard's comment into an answer:$$J_{1^n} = p_{1^n} = \alpha^n n! \sum_{\lambda \vdash n} \frac{J_\lambda}{j_\lambda}$$where $j_\lambda = \langle J_\lambda, J_\lambda \rangle$ is an explicit...
View ArticlePower sums and Jack symmetric functions
Let $\Lambda$ be the algebra of symmetric functions in infinitely many variables over $\mathbb{C}$.The $n$-th power sum symmetric function $p_n$ is defined (formally) as \begin{equation}p_n=\sum_i...
View Article
More Pages to Explore .....